HackerRank 3D Surface Area

https://www.hackerrank.com/challenges/3d-surface-area/problem

提出

code: python

#!/bin/python3

import math

import os

import random

import re

import sys

# Complete the 'surfaceArea' function below.

# The function is expected to return an INTEGER.

# The function accepts 2D_INTEGER_ARRAY A as parameter.

def surfaceArea(A, H, W):

# Write your code here

# print(A)

# 1, 3, 4], 2, 2, 3, [1, 2, 4

# 9, (1+2+4), 9, (1+3+4), (1+2+1), (4+3+4), 5, 7

first = H * W

second = 0

for i in A:

if __name__ == '__main__':

fptr = open(os.environ'OUTPUT_PATH', 'w')

first_multiple_input = input().rstrip().split()

H = int(first_multiple_input0)

W = int(first_multiple_input1)

A = []

for _ in range(H):

A.append(list(map(int, input().rstrip().split())))

result = surfaceArea(A, H, W)

fptr.write(str(result) + '\n')

fptr.close()

code: python

#!/bin/python3

import math

import os

import random

import re

import sys

# Complete the 'surfaceArea' function below.

# The function is expected to return an INTEGER.

# The function accepts 2D_INTEGER_ARRAY A as parameter.

def surfaceArea(A):

# Write your code here

# print(A)

# 1, 3, 4], 2, 2, 3, [1, 2, 4

# top and buttom

area = 2 * H * W

# checks the limit

def check(i, j):

return Ax+iy+j if 0 <= x+i < H and 0 <= y+j < W else 0

# remaining surfaces

xi = 0, 0, 1, -1

yi = 1, -1, 0, 0

for x in range(H):

for y in range(W):

# (0, 1), (0, -1), (1, 0), (1, 1)

for i, j in zip(xi, yi):

# gives area from adjacent cells

area += max(0, Axy - check(i, j))

return area

if __name__ == '__main__':

fptr = open(os.environ'OUTPUT_PATH', 'w')

first_multiple_input = input().rstrip().split()

H = int(first_multiple_input0)

W = int(first_multiple_input1)

A = []

for _ in range(H):

A.append(list(map(int, input().rstrip().split())))

result = surfaceArea(A)

fptr.write(str(result) + '\n')

fptr.close()

メモ

https://www.youtube.com/watch?v=GYaLhyfGRhM

提出

code: python

#!/bin/python3

import math

import os

import random

import re

import sys

# Complete the 'surfaceArea' function below.

# The function is expected to return an INTEGER.

# The function accepts 2D_INTEGER_ARRAY A as parameter.

def surfaceArea(A, H, W):

# Write your code here

# 9 + 9 + 11 + 10 + 10 + 11

topNum = H * W

downNum = H * W

front = []

frontAns = []

# A = 1, 3, 4], 2, 2, 3, [1, 2, 4

for a in A:

front.append([a0])

frontAns.append(a0)

for i in range(len(A)):

for j, a in enumerate(Ai):

if j == 0:

continue

else:

if a > fronti-1:

frontAns.append(a - fronti-1)

fronti.append(a)

frontNum = sum(frontAns)

B = []

back = []

backAns = []

for a in A:

B.append(list(reversed(a)))

# B = 4, 3, 1], 3, 2, 2, [4, 2, 1

for b in B:

back.append([b0])

backAns.append(b0)

for i in range(len(A)):

for j, b in enumerate(Bi):

if j == 0:

continue

else:

if b > backi-1:

backAns.append(b - backi-1)

backi.append(b)

backNum = sum(backAns)

L = [[] for _ in range(len(A))]

left = []

leftAns = []

for i in range(len(A)):

for a in A:

Li.append(ai)

# L = 1, 2, 1], 3, 2, 2, [4, 3, 4

for l in L:

left.append([l0])

leftAns.append(l0)

for i in range(len(A)):

for j, l in enumerate(Li):

if j == 0:

continue

else:

if l > lefti-1:

leftAns.append(l - lefti-1)

lefti.append(l)

leftNum = sum(leftAns)

R = []

right = []

rightAns = []

for l in L:

R.append(list(reversed(l)))

# R = 1, 2, 1], 2, 2, 3, [4, 3, 4

for r in R:

right.append([r0])

rightAns.append(r0)

for i in range(len(A)):

for j, r in enumerate(Ri):

if j == 0:

continue

else:

if r > righti-1:

rightAns.append(r - righti-1)

righti.append(r)

print(rightAns)

rightNum = sum(rightAns)

return topNum + downNum + frontNum + backNum + leftNum + rightNum

if __name__ == '__main__':

fptr = open(os.environ'OUTPUT_PATH', 'w')

first_multiple_input = input().rstrip().split()

H = int(first_multiple_input0)

W = int(first_multiple_input1)

A = []

for _ in range(H):

A.append(list(map(int, input().rstrip().split())))

result = surfaceArea(A, H, W)

fptr.write(str(result) + '\n')

fptr.close()